Introduction:
Solving deals with the variable, the variables are in the form of alphabets, such as x, y, z, m, n. Using this we can create any expressions in the equation form and find the value of variables. This article we will be discussing about solving for x in math. Mostly we use mathematical expression assigned with the variable x only. Basically algebra equations also use the variable x in math. Now we are solving some equation with x variable. Having problem with Dividing Radical Expressions keep reading my upcoming posts, i will try to help you.
Examples problems:
Example 1: Solve for x term in the given equation, 9x + 6 = 5x + 10
Solution:
Step 1: First we write the given expression for solving i.e. arrange the expression in correct form.
9x + 6 = 5x + 10
Step 2: Arrange in order for the constant values to right side; In this case first we have to subtract with 6 on both sides.
(9x + 6) – 6 = (5x + 10) – 6
9x = 5x + 4
Step 3: We have to subtract with 5x on both sides. Then arrange the coefficient of x values to the left side.
9x – 5x = (5x + 4) – 5x
4x = 4
Step 4: If possible, eliminate the coefficient values in the left side by dividing or multiplying. Now, we eliminate the coefficient of x, where the coefficient of x value is 4. So, we divide 4 on both sides.
4x/4 = 4/4
Step 5: Thus, the solution is obtained.
x = 1
Example 2: Solve for x term in the given equation, 8x - 5 = 3x + 25.
Solution:
Step 1: First we write the given expression for solving; arrange the expression in correct form.
8x - 5 = 3x + 25
Step 2: Arrange in order for the constant values to right side; In this case first we have to add with 5 on both sides.
(8x - 5) + 5 = (3x + 25) + 5
8x = 3x + 30
Step 3: We have to subtract with 3x on both sides. Then arrange the coefficient of x values to the left side.
(8x) – 3x = (3x + 30) – 3x
5x = 30
Step 4: If possible, eliminate the coefficient values in the left side by dividing or multiplying. Here, we eliminate the coefficient of x, where the coefficient of x value is 5. So, we divide 5 on both sides.
5x/5 = 30/5
Step 5: Thus, the solution is obtained.
x = 6
Please express your views of this topic Complete the Square Solver by commenting on blog.
Practice problems:
1. Solve for x in math to given equation, 2x + 2x = 8
Answer is x = 2.
2. Solve for x in math to given equation, 3x + 2 = 5x – 8
Answer is x = 5.
3. Solve for x in math to given equation, 6x - 4 = 2x + 8
Answer is x = 3.
4. Solve for x in math to given equation, 2x - 4 = x + 8
Answer is x = 12.
5. Solve for x in math to given equation, 8x - 14 = 4x + 2
Answer is x = 4.
Solving deals with the variable, the variables are in the form of alphabets, such as x, y, z, m, n. Using this we can create any expressions in the equation form and find the value of variables. This article we will be discussing about solving for x in math. Mostly we use mathematical expression assigned with the variable x only. Basically algebra equations also use the variable x in math. Now we are solving some equation with x variable. Having problem with Dividing Radical Expressions keep reading my upcoming posts, i will try to help you.
Examples problems:
Example 1: Solve for x term in the given equation, 9x + 6 = 5x + 10
Solution:
Step 1: First we write the given expression for solving i.e. arrange the expression in correct form.
9x + 6 = 5x + 10
Step 2: Arrange in order for the constant values to right side; In this case first we have to subtract with 6 on both sides.
(9x + 6) – 6 = (5x + 10) – 6
9x = 5x + 4
Step 3: We have to subtract with 5x on both sides. Then arrange the coefficient of x values to the left side.
9x – 5x = (5x + 4) – 5x
4x = 4
Step 4: If possible, eliminate the coefficient values in the left side by dividing or multiplying. Now, we eliminate the coefficient of x, where the coefficient of x value is 4. So, we divide 4 on both sides.
4x/4 = 4/4
Step 5: Thus, the solution is obtained.
x = 1
Example 2: Solve for x term in the given equation, 8x - 5 = 3x + 25.
Solution:
Step 1: First we write the given expression for solving; arrange the expression in correct form.
8x - 5 = 3x + 25
Step 2: Arrange in order for the constant values to right side; In this case first we have to add with 5 on both sides.
(8x - 5) + 5 = (3x + 25) + 5
8x = 3x + 30
Step 3: We have to subtract with 3x on both sides. Then arrange the coefficient of x values to the left side.
(8x) – 3x = (3x + 30) – 3x
5x = 30
Step 4: If possible, eliminate the coefficient values in the left side by dividing or multiplying. Here, we eliminate the coefficient of x, where the coefficient of x value is 5. So, we divide 5 on both sides.
5x/5 = 30/5
Step 5: Thus, the solution is obtained.
x = 6
Please express your views of this topic Complete the Square Solver by commenting on blog.
Practice problems:
1. Solve for x in math to given equation, 2x + 2x = 8
Answer is x = 2.
2. Solve for x in math to given equation, 3x + 2 = 5x – 8
Answer is x = 5.
3. Solve for x in math to given equation, 6x - 4 = 2x + 8
Answer is x = 3.
4. Solve for x in math to given equation, 2x - 4 = x + 8
Answer is x = 12.
5. Solve for x in math to given equation, 8x - 14 = 4x + 2
Answer is x = 4.
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