Math Sentence For Kids

Introduction to word problems:

Word problems are sentences describing a mathematical question.  It is an alternative method of expressing different mathematical problems. Word problems are simple sentences mainly used to explain a practical situation where mathematical operations or application is used.

Few important words used in word problems are :

Sum, altogether ------  all stands for  `addition (+)`
Substract, take away, left over -----all  stands for ` minus (-)`
Times, product -------- all stands for `"multiply" ( * )`
A simple way to explain addition or substraction to kids is by forming simple sentences. Kids can relate more easily to simple sentences than mathematical symbol.

I like to share this Derivative of Integral with you all through my article.

Simple word problems on addition:


Ex 1: Mary had 3 cookies.  John had 5 cookies. How may cookies do they have altogether?

Sol: Step 1:  First we will try to find the word which describes mathematical operation

In this question, word is "altogether", means we have to perform addition

Step 2:  Mary -------- 3 cookies

John --------- 5 cookies

Step 3: Total -------  Add 3 and 5

So,  3 + 5 = 8 cookies

Ex 2: Alice had 2 pencils.  Her mother gave her 3 pencils.  How many pencils do Alice altogether?

Ans: Alice has 5 pencils

Ex 3: In a box, there are 5 candies. If Joe put 8 more candies in the box, then how many candies are there in the box altogether?

Ans:  There will be 13 candies in the box altogether


Simple word problems on subtraction:


Ex 1: Matt had 10 oranges.  He made juices out of 6 organes then how many oranges are left?

Sol: Step 1: First we will try to find the word which describes mathematical operation

In this question, word is "left", means we have to perform subtraction

Step 2:  Matt had 10 oranges

6 oranges were used for taking juice

Step 3:  10 - 6 = 4

Remaining will be 4 oranges

Ex 2: 15 posters were pasted all over the school. If 5 were removed, then how many were left?

Ans:  10 posters

Ex 3: Sally had 8 dolls.  She gave 3 dolls to her cousin.  How many dolls does Sally have left?

Ans: 5 dolls

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Simple word problems on multiplication:


Ex:  Cost of one banana is $ 5. Jack buys 3 bananas. What is the total cost of 3 bananas?

Cost of 3 bananas is $ 15

Ex 2:  What is the product of 5 and 6?

Ans: 30

Ex 3:  Mike's paper boat measures 2 inches. Mike's dad makes a paper boat 4 times bigger than Mike's. What is the measure of dad's boat?

Ans:  Dad's boat is 8 inches.

Solve For X in Math

Introduction:

Solving deals with the variable, the variables are in the form of alphabets, such as x, y, z, m, n. Using this we can create any expressions in the equation form and find the value of variables. This article we will be discussing about solving for x in math. Mostly we use mathematical expression assigned with the variable x only. Basically algebra equations also use the variable x in math. Now we are solving some equation with x variable. Having problem with Dividing Radical Expressions keep reading my upcoming posts, i will try to help you.


Examples problems:


Example 1: Solve for x term in the given equation, 9x + 6 = 5x + 10

Solution:

Step 1: First we write the given expression for solving i.e. arrange the expression in correct form.

9x + 6 = 5x + 10

Step 2: Arrange in order for the constant values to right side; In this case first we have to subtract with 6 on both sides.

(9x + 6) – 6 = (5x + 10) – 6

9x = 5x + 4

Step 3: We have to subtract with 5x on both sides. Then arrange the coefficient of x values to the left side.

9x – 5x = (5x + 4) – 5x

4x = 4

Step 4: If possible, eliminate the coefficient values in the left side by dividing or multiplying. Now, we eliminate the coefficient of x, where the coefficient of x value is 4. So, we divide 4 on both sides.

4x/4 = 4/4

Step 5: Thus, the solution is obtained.

x = 1

Example 2: Solve for x term in the given equation, 8x - 5 = 3x + 25.

Solution:

Step 1: First we write the given expression for solving; arrange the expression in correct form.

8x - 5 = 3x + 25

Step 2: Arrange in order for the constant values to right side; In this case first we have to add with 5 on both sides.

(8x - 5) + 5 = (3x + 25) + 5

8x = 3x + 30

Step 3: We have to subtract with 3x on both sides. Then arrange the coefficient of x values to the left side.

(8x) – 3x = (3x + 30) – 3x

5x = 30

Step 4: If possible, eliminate the coefficient values in the left side by dividing or multiplying. Here, we eliminate the coefficient of x, where the coefficient of x value is 5. So, we divide 5 on both sides.

5x/5 = 30/5

Step 5: Thus, the solution is obtained.

x = 6

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Practice problems:


1. Solve for x in math to given equation, 2x + 2x = 8

Answer is x = 2.

2. Solve for x in math to given equation, 3x + 2 = 5x – 8

Answer is x = 5.

3. Solve for x in math to given equation, 6x - 4 = 2x + 8

Answer is x = 3.

4. Solve for x in math to given equation, 2x - 4 = x + 8

Answer is x = 12.

5. Solve for x in math to given equation, 8x - 14 = 4x + 2

Answer is x = 4.

Answer Key Book for Math

Introduction to answer key book for math :

In this article, we are going to discuss about the answer key book for math, The arithmetic operators are the basics in mathematics which includes addition, subtraction, division and multiplication. The basic arithmetic operators have more advanced operations, which includes square roots of algebraic equation, exponentiation, logarithmic functions, etc. Solution and answering methods or keys for the example problems are explained here.  Answer for the test would be in the form of objective type. Let us see the some examples in answer key book for math. Having problem with Integrals of Inverse Trig Functions keep reading my upcoming posts, i will try to help you.


Example problems in answer key book for math:


Math book problem 1:

A survey showed that `4/5` of a newspaper’s readers had access to a computer during the day. What is `4/5` written as a percent?

75%
80%
65%
90%

Solution: 2) 80 %

Answer key :

`4/5`   written as percent

`4/5` * 100 = `400/5` = 80%

Math book problem 2 :

What is the value for the expression given below?
4 - 23 * 3

-20
-14
18
24

Solution:  1)  -20.

Answer key:

4 - 23 * 3 = 4 - 8 * 3

= 4 - 24

= -20

Math book problem 3 :

Laural's average score on five mathematics tests is 90. What is the sum of the scores of Laural’s five tests?

368
450
474
372

Solution:   2)  450

Answer key :

Laural’s mean score on five mathematics tests is 90

so, here average of all the subject is 95 the total score is 90 * 5 = 450 marks

I have recently faced lot of problem while learning 6th grade math questions and answers, But thank to online resources of math which helped me to learn myself easily on net.

Practice problems in answer key book for math:


Problem 1:

In a fancy shop, there are 12 toys, 18 balls, 24 dolls and 5 notebooks. Find the total number of fancy items in the shop?

Problem 2:

John has 24 pens and 3 scales and he gave 19 pens and 1 scale to his friend. calculate the remaining pencils and scales the john has?

Problem 3:

There are 15 boys in a class. The book seller sold 8 books to each boy. Find the total number of books sold by the seller.

Problem 4:

James has 24 fishes. He gave 6 fishes each to his friends. Find the total number of friends he have.

Problem 5:

A survey showed that 5/8 of a newspaper’s readers had access to a mobile in the office. What is 5/8 written as a percent?

problem 6:

Mac’s mean score on Three mathematics tests is 85. What is the sum of the scores of Mac’s Three tests?

Answer keys

i).59 items in the shop

ii).5 pens and 2 scales

iii).120 books

iv).4 friends

v).62.5 percent.

vi).255 total score.

Basic Math Calculator

Introduction to basic math calculator:
In general, calculators are used to perform various operations. Mathematical calculators perform both simple and complex operations. Basic mathematical calculators are used to perform various simple mathematical operations such as addition, subtraction, multiplication, division etc.,

In this article of basic math calculator, we are going to discuss about various simple mathematical operations using calculators. Is this topic Adding Negative Numbers hard for you? Watch out for my coming posts.


Basic Addition and Subtraction Calculator:


Examples for addition calculator:

1) 19 + 27 = ?

Step 1: Enter the numbers 19

Step 2: Press the + sign

Step 3: Enter the numbers 27

Step 4: If we press = sign, the result can be obtained as 46.

2) 712 + 323 = ?

Step 1: Enter the numbers 712

Step 2: Press the + sign

Step 3: Enter the numbers 323

Step 4: If we press = sign, the result can be obtained as 1035.

Examples for subtraction calculator:

1) 120 - 70 = ?

Step 1: Enter the numbers 120

Step 2: Press the - sign

Step 3: Enter the numbers 70

Step 4: If we press = sign, the result can be obtained as 50.

2) 347 - 127 = ?

Step 1: Enter the numbers 347

Step 2: Press the - sign

Step 3: Enter the numbers 127

Step 4: If we press = sign, the result can be obtained as 220.

I have recently faced lot of problem while learning Double Digit Subtraction, But thank to online resources of math which helped me to learn myself easily on net.

Basic Multiplication and Division Calculator:


Examples for multiplication:

1) 10  * 35 = ?

Step 1: Enter the numbers 10

Step 2: Press the  *  sign

Step 3: Enter the numbers 35

Step 4: If we press = sign, the result can be obtained as 350.

2) 72  * 37 = ?

Step 1: Enter the numbers 72

Step 2: Press the  *  sign

Step 3: Enter the numbers 37

Step 4: If we press = sign, the result can be obtained as 2664.

Examples for Division:

1) 120/ 6 = ?

Step 1: Enter the numbers 120

Step 2: Press the  /   sign

Step 3: Enter the number 6

Step 4: If we press = sign, the result can be obtained as 20.

2) 462 / 12 = ?

Step 1: Enter the numbers 462

Step 2: Press the  /  sign

Step 3: Enter the number 12

Step 4: If we press = sign, the result can be obtained as 38.5.

3) 5246 / 242 = ?

Step 1: Enter the numbers 5246

Step 2: Press the  /  sign

Step 3: Enter the numbers 242

Step 4: If we press = sign, the result can be obtained as 21.677.

Fourth Grade Math Terms

Introduction to fourth grade math terms:

Preparation of math terms is an essential one because it provides the foundation for solving various mathematical problems and also for learning basic operations in math.

In this article of fourth grade math terms,various basic math terms related to fourth grade are given.


Fourth grade math terms:


Algebraic equation

It refers to any equation that contains only algebraic expressions and signs of operations.

Area

The Area of a region is the number of square units that it takes to cover the region.

Circle

A circle is the path traced by a point which moves in a plane in such a way that its distance from a fixed point remains constant.

Collinear points

If three or more points lie on th same line, then they are called collinear points.

Complementary  angles

Two angles are said to be complementary if the sum is equal to 90o

Concurrent lines

If two or more straight lines pass through the same point, then they are called concurrent lines. The point through which the lines pass is known as point of concurrency.

Equivalent fractions

Fractions that show the same amount are called equivalent fractions.

Even numbers

The numbers, which are divisible by two are called even numbers

Improper fraction

A fraction whose numerator is equal to or greater than the denominator is called improper fraction.

Integers

All natural numbers , 0 and negatives of natural numbers form integers.

Irrational numbers

A number which cannot be put in the form a/b, where a and b are integers and a is not equal to zero, is called an irrational number.

Like terms

Terms that differ in their numerical coefficients but do not differ in symbol are called like terms. Please express your views of this topic Function Calculator by commenting on blog.


Additional Fourth grade math terms:


Mixed fraction

The sum of a whole number and a proper fraction is called as mixed fraction.

Natural Numbers

To count a given number of objects, we use numbers, which we call counting numbers or natural numbers. The numbers 1,2,3,4... are called natural numbers.

Odd numbers

The numbers, which are not divisible by two, are called odd numbers.

Proper fraction

A fraction whose numerator is less than its denominator is called a proper fraction.

Rational numbers

The numbers of  the form a/b,where a and b are integers and a is not equal to zero, are known as rational numbers.

Supplementary angles

The two angles are said to be Supplementary if the sum is equal to180o.

Unlike terms

Terms may or may not differ in their numerical coefficient are called unlike terms.

Volume

The quantity of matter contained in a solid is called volume.

Whole numbers

All natural numbers together with 0 form whole numbers.

Easy Help for Math Integers

Introduction:

Integers are numbers which doesn't contain decimal and fractions point in them. Integers are numbers in both positive and negative direction (-9, -8, -7, 0, 7, 8, 9). In other words, integers are the whole numbers with both positive and negative sign (where zero has no sign). The numbers like 34.6 ,51/4 cannot be said as integers. Integers are used everywhere in mathematics, Since they are the important elements to form math. Easy help for math integers involves the basic operation of addition and subtraction of integers. I like to share this Adding Integers with you all through my article.


Examples for Integer addition:

Here are few examples for easy help on addition of  math integers,

Example 1:

Find the sum of the integers, 23 and 45.

Solution:

The easy help for adding two integers is as follows,

2     4

(+)4      5

6      9

Example 2:

Find the sum of the integers, 133 and 155.

Solution:

The easy help for adding two integers is as follows,

1     3     4

(+)1     5      5

2      8      9

Example 3:

Find the sum of the integers, 34 and 55.

Solution:

The easy help for adding two integers is as follows,

3     4

(+)5      5

8      9

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Examples for Integer subtraction:


Here are few examples for easy help on subtraction of  math integers,

Example 1:

Find the difference between the integers,  45 and 23

Solution:

The easy help for subtracting two integers is as follows,

4     5

(-)2      3

2      2

Example 2:

Find the difference between the integers, 155 and 133.

Solution:

The easy help for subtracting two integers is as follows,

1     5     5

(-)1     3      3

0      2      2

Example 3:

Find the difference between the integers, 55 and 33.

Solution:

The easy help for subtracting two integers is as follows,

5     5

(-)3     3

2      2

Help with Pre Algebra Math

Introduction help with pre-algebra math:

A pre-algebra math is a study of basic mathematic operations and math’s functions. Mathematics is a one of a language and logic thing of science. This is an essential tool, medicine and the geography fields. In mathematics concept and fundamental concept are arithmetic operations. The basic arithmetic operations for math are addition of a integer values, and subtraction of an integer values, and division of an integer values and multiplication of an integer values.  This type of math problems help to lower grade algebra is deals with pre algebra, math and geometry problems.In this article we shall discuss for help with pre-algebra math.

I like to share this algebra 2 word problems and answers with you all through my article.

Sample problem for help with pre algebra math:

Problem 1:

Solve the given linear equations and find out the x value x – 8 = 10

Solution:

Find out the x value of the given linear equation.

we are move the -8 into the right side, we get
X = 10 + 8

X = 18.

The x value of an equation is 18.

Problem 2:

Find the value of the given numerical values 18 + (10 * 12)

Solution:

We are going to find the value of given data.

In the first we are going to multiply the terms 10 and 12, we get

10 * 12 = 120

In the next step we are going to add the terms 18 and 120, we get

18 + 120 = 138

The value of the given equation is 138.

Problem 3:

Find the co-efficient of linear equation 6x2 + 10y2 = 0

Solution:

find the co-efficient value of the x and y terms.

we are going to find the x co-efficient value.
X co-efficient is 6

In the next step we are going to find the y co-efficient value.

Y co-efficient is 10.

Understanding Laws of Probability is always challenging for me but thanks to all math help websites to help me out.

Practice problem for help with pre algebra math:

Solve the given linear equations and find out the x value x – 2 = 5
Answer: x = 7

Solve the given linear equations and find out the x value x + 2 = 3
Answer: x = 1

Types of Interest in Math

Interest is classified into two types. They are:

Simple interest

Compound interest

Simple interest: Simple interest is money we can earn by primarily investing some amount in bank or somewhere else (the principal). The percentage (the interest) of the principal amount is added to the principal, simple interest will increase our initial investments grow.

Compound interest: The difference between the original principal and the amount at the end of the last time period is known as the compound interest on the original principal period for that.

The important difference between compound and simple interest is  that simple interest is paid only on the principal, whereas compound interest is paid on both the principal and the accumulated interest.


Interest formula


Simple interest formula:

The formula used for calculating the simple interest is

SI = `(PNR)/100`

Where,

P is the Principal,

N is the time period,

R is the rate of interest.

Compound interest formula:

The formula used for calculating the compound interest is

A = P (1 + `r / 100` )n

Where,

P is the Principal

R is the rate of interest

N is the number of years.


Solved Examples


Pro 1: Find the simple interest on an amount of $500 for one year at the rate of 6% per annum.

Sol: The formula is SI = PNR / 100

Principal (P) = $500

Rate of interest(r) = 6 % per annum

N= Interest on 100 dollar for 1 year = $6

Interest on 500 dollar for 1 year =6 / 100 × 500 = $30

Therefore the interest is $30.

Pro 2: Find the amount of and compound interest on $6000 for 3 years at 3% per annum.

Sol: Let p1, p2, p3… represents the principal for the first year, second year, third year and so on. Also let I1, I2, I3… represent interest for the first year, second year, third year and so on.

Understanding Definition of Compound Interest is always challenging for me but thanks to all math help websites to help me out.

The formula is A = P (1 +` r / 100` )n

C.I. = A – P

P = $6000, r = 3%, n = 3 years

A = P (1 + `r / 100` )` ^n ` = 6000 (1 + `3 / 100` )3

= 6000 (`103 / 100)` 3

= 6000 * 103 * 103 * 103 / 100 * 100 * 100

= 6556.36

Therefore

A = $6556.36

P = $6000

C. I. = A – P = 6556.36 – 6000 = 556.36
C. I. = $556.36

Pro 3: Find the amount and compound interest on 5000 dollars for 1.5 years at 8%per annum. Interest being is added to the principal every half year.

Sol: P = 5000dollars, n= 3 (three half years), r = `8/ 2` = 4%

A = P (1+`r / 100)` n = 5000 (1+4) / 100 3

= 5000 (`104 / 100` )3

= `(5000*104*104*104) / (100*100*100)` =5624.32dollars

A = 5624.32

Compound Interest = A – P = 5624.32 – 5000

= 624.32dollars.

Pro 4:  Find the solution of simple interest, where total amount is 80,000, rate is 0.04 for per annum.

Sol: Simple interest = P*N*R.

=80000 *0.04 * 1.

=3200.

The simple interest is 3200.

Pro 5: Find the solution of simple interest, where total amount is 1,00,000, rate is 0.09 for per annum.

Sol: Simple interest = P*N*R.

=1,00,000 *0.09 * 1.

=9000.

The simple interest is 9000.

Math Terms Division

Introduction to math terms division:
In mathematics, especially in elementary arithmetic, division (÷) is the arithmetic operation that is the inverse of multiplication.

Specifically, if c times b equals a, written: C = b x a

where b is not zero, then a divided by b equals c, written: `a/b = c`

For instance, `6/3 = 2`

since  2 x 3 = 6

In the above expression, a is called the dividend, b the divisor and c the quotient. I like to share this Simplify Algebraic Expressions with you all through my article.


Math terms division:


Math term division type -1:

Division of 2 numbers with the same sign should be ‘+’ ve (positive sign) sign.

‘+’ve (Positive number) ÷’+’ve ( positive number) = ‘+’ve ( positive number)
‘-‘ve (Negative number) ÷ ‘-‘ ve (negative number) = =’+’ ve (positive number)
Math term division type - 2:

Division of 2 numbers with different signs should be ‘-’ve negative

‘+’ve (Positive number) ÷(‘-‘ve negative number) = ‘-‘ve (negative number)
‘-‘ve (Negative number) ÷ ‘+’ve (positive number) = ‘-‘ve (negative number)
Examples on math terms division :

Ex : 42 ÷ 7 = 6 (same signs)

(-26) ÷ (-2) = 13 (same signs)

6 ÷ (-2) = -3 (different signs)

(-10) ÷ 10 = -1 (different signs)

Math Terms Division on Dividing Variable:
In this operation division represents dividing the variables based on the presence of values.

Ex: Solve the following division: 54 ÷ p, given that p = -6

Solution:54 ÷ p

Substitute p = -6,

= 54 ÷ (-6)

= -9 (dissimilar signs).

Understanding Sig Fig Rules is always challenging for me but thanks to all math help websites to help me out.

Math Terms Division Of Dividing Decimal:


Math terms division for solving decimal problems:

Math term division of decimals type - 1:To create the decimal divisor as whole number by changing the decimal point to the right side.
Math term divison of decimals type - 2:To change the same decimal point in the dividend to the right side to create as whole number
Math term  division of type - 3:After divide the new dividend or whole number by new divisor or whole number


Ex:Divide the following decimal function:  24.24 ÷ 0.20

Solution:   24.24 ÷ 0.20 = `24.24/0.20`

= `242.4/2`  (Take the decimal divisor as whole number)

= `2424/20`  (Take the decimal dividend as whole number)

= 121.2 (Divide the new dividend by new divisor).