Question : The Square based pyramid depicted below has averticle height of 13cm. K is the mid point of CD and angle AKL =50 degrees. To the nearest tenth of degree, what is the measure of angle ACK?
Solution :
Length of Square be x Tan 50º = 1.19175 = 13 / (x/2) x = 21.81659041 x = 21.82 Sin 50º = (x/2) / AK AK = (x/2) / 0.766 AK = 14.24 Tan ∟AKC = AK /(x/2) = 14.24/ 10.91 = 1.31 ∟AKC = tanˉ¹(1.31)
Topic : Trapezium Question : The area of a trapezium shaped field is 960 m^2 , the distance between two parallel sides is 10 m and one of the parallel side is 40m. Find the other parallel side.
Solution : One of the parallel side a = 40 m, let another parallel side be x, distance between sides (h) = 10 m The given area of trapezium = 960m^2. Area of a trapezium = ½ h (a + b) so 960 = ½ h (a + b) = ½ x 10 x (40 + x) or 960 = 5( 40 + x) or 960/5 = 40 + x or 192 = 40 + x or 192 – 40 = x x = 152 m the other parallel side of the trapezium is 152 m.