In Number Theory Tutorial ,an expression or string of symbols is intended to represent a numerical value; a properly-formed expression may be evaluated in an unambiguous way. But in practice, an expression with multiple terms and operators may be written without parentheses, in which case the intended value of the expression is determined by convention. When we evaluate the expression is both preceded and followed by an operator such as minus or times, a convention is needed to clarify which operator should be applied first; this rule is known as a precedence rule, or more informally order of operation. From the earliest use of mathematical notation[citation needed], multiplication took precedence over addition, whichever side of a number it appeared on. Thus 3 + 4 × 5 = 5 × 4 + 3 = 23. When exponents were first introduced, in the 16th and 17th centuries, exponents took precedence over both addition and multiplication, and could be placed only as a superscript to the right of their base. Thus 3 + 5 2 = 28 and 3 × 5 2 = 75. To change the order of operations, a vinculum (an overline or underline) was originally used. Today one uses parentheses (). Thus, if one wants to force addition to precede multiplication, one writes (3 + 4) × 5 = 35.We can use order of operations calculator as well.
Mnemonics are often used to help students remember the rules. One common strategy is to build an acronym from the names of the operations. For instance, in the United States, the acronym PEMDAS (for Parentheses, Exponentiation, Multiplication/Division, Addition/Subtraction) is used, sometimes expressed as the sentence "Please Excuse My Dear Aunt Sally" or one of many other variations. In other English speaking countries, Parentheses may be called Brackets, and Exponentiation may be called Indices, Powers or Orders. Also, as Multiplication and Division are of equal precedence, M and D may be interchanged in the mnemonic. (This does not mean that multiplication and division can be performed in any arbitrary order, just that it is wrong to say "M always comes before D", or "D comes before M". See below.) The same comments apply to Addition and Subtraction.
Question:-
Solve 2 - [ (7-6) + (9-19)]
Answer:-
2 - [ (7-6) + (9-19)]
Here we have many signs.
When we have more than one sign ,we have to apply PEMDAS rule
= 2 - [ (1) + (-10)]
We have to solve inside the parenthesis first
Here (+) (-) = -
= 2 - [ 1 - 10]
= 2 - [-9]
Here (-) (-) = +
= 2+9
= 11 is the Answer
Monday, August 31
Wednesday, August 19
A problem on simple interest
Interest is a fee paid on borrowed assets. It is the price paid for the use of borrowed money, or, money earned by deposited funds.Assets that are sometimes lent with interest include money, shares, consumer goods through hire purchase, major assets such as aircraft, and even entire factories in finance lease arrangements. The interest is calculated upon the value of the assets in the same manner as upon money. Interest can be thought of as "rent of money". For example, if you want to borrow money from the bank, there is a certain rate you have to pay according to how much you want loaned to you.
Let's see a problem on this from 8th grade math worksheets
Question:-
What is the interest earned on # 97500 when rate of interest is 8% and for 5 months?
Answer:-
Here is the solution from answers to math problems
This problem based on simple interest.
The formula for simple interest is
R=rate of interest =8%
T=Time of year=5 months
=5/12 in years
I=interest amount
We have to put these values in formula
This is a part of elementary algebra practice .
Simple interest is calculated only on the principal amount, or on that portion of the principal amount which remains unpaid.
The amount of simple interest is calculated according to the following simple interest formula:
Let's see a problem on this from 8th grade math worksheets
Question:-
What is the interest earned on # 97500 when rate of interest is 8% and for 5 months?
Answer:-
Here is the solution from answers to math problems
This problem based on simple interest.
The formula for simple interest is
p x T x R
I= ------------
100
p= principle=$97500R=rate of interest =8%
T=Time of year=5 months
=5/12 in years
I=interest amount
We have to put these values in formula
97500 x 8 x 5
I= --------------
100 x 12
3900000
I = ----------
1200
I=3250
So the total interest earned on $97500 is $3250.This is a part of elementary algebra practice .
Thursday, August 13
Problem on mean median mode range
This math help is for mean median mode range worksheets
Mean, median, and mode are three kinds of "averages".
The "mean" is the "average" you're used to, where you add up all the numbers and then divide by the number of numbers.
The "median" is the "middle" value in the list of numbers. To find the median, your numbers have to be listed in numerical order, so you may have to rewrite your list first.
The "mode" is the value that occurs most often. If no number is repeated, then there is no mode for the list.
The "range" is just the difference between the largest and smallest values.
EXAMPLE:-
Find the mean, median, mode, and range for the following list of values:
8, 9, 10, 10, 10, 11, 11, 11, 12, 13
The mean is the usual average:
(8 + 9 + 10 + 10 + 10 + 11 + 11 + 11 + 12 + 13) ÷ 10 = 105 ÷ 10 = 10.5
The median is the middle value. In a list of ten values, that will be the (10 + 1) ÷ 2 = 5.5th value; that is, average of the fifth and sixth numbers to find the median:
(10 + 11) ÷ 2 = 21 ÷ 2 = 10.5
The mode is the number repeated most often. This list has two values that are repeated three times.10 and 11.
The largest value is 13 and the smallest is 8,
so the range is 13 – 8 = 5.
So
mean: 10.5
median: 10.5
modes: 10 and 11
range: 5
For more help on this ,you can reply me.
Mean, median, and mode are three kinds of "averages".
The "mean" is the "average" you're used to, where you add up all the numbers and then divide by the number of numbers.
The "median" is the "middle" value in the list of numbers. To find the median, your numbers have to be listed in numerical order, so you may have to rewrite your list first.
The "mode" is the value that occurs most often. If no number is repeated, then there is no mode for the list.
The "range" is just the difference between the largest and smallest values.
EXAMPLE:-
Find the mean, median, mode, and range for the following list of values:
8, 9, 10, 10, 10, 11, 11, 11, 12, 13
The mean is the usual average:
(8 + 9 + 10 + 10 + 10 + 11 + 11 + 11 + 12 + 13) ÷ 10 = 105 ÷ 10 = 10.5
The median is the middle value. In a list of ten values, that will be the (10 + 1) ÷ 2 = 5.5th value; that is, average of the fifth and sixth numbers to find the median:
(10 + 11) ÷ 2 = 21 ÷ 2 = 10.5
The mode is the number repeated most often. This list has two values that are repeated three times.10 and 11.
The largest value is 13 and the smallest is 8,
so the range is 13 – 8 = 5.
So
mean: 10.5
median: 10.5
modes: 10 and 11
range: 5
For more help on this ,you can reply me.
Monday, July 20
A word problem on percentages
Percentages are used to express how large one quantity is, relative to another quantity. The first quantity usually represents a part of, or a change in, the second quantity, which should be greater than zero. For example, an increase of $ 0.15 on a price of $ 2.50 is an increase by a fraction of 0.15 / 2.50 = 0.06. Expressed as a percentage, this is therefore a 6% increase.
Let's see a word problem on it.
Question:-
A waitress earn an average tip of 12% of the cost of the food she serves.If she serves $ 375 worth of food in one evening ,how much money in tips will she earn on average.
Answer:-
Let's see a word problem on it.
Question:-
A waitress earn an average tip of 12% of the cost of the food she serves.If she serves $ 375 worth of food in one evening ,how much money in tips will she earn on average.
Answer:-
Waitress serves food worth=$375For more help on this,you can reply me.
She earns a tip=12%
So.
12% of $375
12
----- * 375
100
12*375
---------
375
4500
= -------
100
=$45
So the waitress earn a tip of $45.
Tuesday, July 7
problem on solving linear equations
Topic:-linear equation
A linear equation is an algebraic equation in which each term is either a constant or the product of a constant and (the first power of) a single variable.
Linear equations can have one or more variables. Linear equations occur with great regularity in applied mathematics. While they arise quite naturally when modeling many phenomena, they are particularly useful since many non-linear equations may be reduced to linear equations by assuming that quantities of interest vary to only a small extent from some "background" state.
Question:-
solve |5b-3| = |3b+7|
So b= 5 or -1/2 is the answer
For more help on this ,please reply me.
A linear equation is an algebraic equation in which each term is either a constant or the product of a constant and (the first power of) a single variable.
Linear equations can have one or more variables. Linear equations occur with great regularity in applied mathematics. While they arise quite naturally when modeling many phenomena, they are particularly useful since many non-linear equations may be reduced to linear equations by assuming that quantities of interest vary to only a small extent from some "background" state.
Question:-
solve |5b-3| = |3b+7|
Answer:-
This math help is from linear equations.
This is of the form |a|=|b|
which implies a = +b
or a = -b
Using this we get
5b-3=+(3b+7)
5b-3=-(3b+7)
5b-3 =+(3b+7)| 5b-3 =-(3b+7)
|
5b-3 = 3b+7 | 5b-3 = -3b-7
|
bring 3b |
left | bring 3b left
hand side | hand side
|
5b-3b=7+3 | 5b+3b= -7+3
|
2b = 10 | 8b= -4
|
b = 5 | b = -4/8
|
| b = -1/2
So b= 5 or -1/2 is the answer
For more help on this ,please reply me.
Monday, June 22
How to solve time and work problems
Topic :- Time and Work
Time and work problems are very important for test preparation when you are out of school for long period .
The time will be given and the amount of work done in that time period needs to be calculated and vice versa .
Here is a simple Time word problem Given ,Which will give an idea of solving workwordproblems
as well.
Question :-
Jim can fill a pool carrying buckets of water in 30 minutes. Sue can do the same job in 45 minutes. Tony can do the same job in 1 ½ hours. How quickly can all three fill the pool together?
Answer:-
Jim can fill the pool in 30 min.
So in 1 min,jim can fill 1/30 th part of pool.
Similarly in 1 min,Sue can fill 1/45th part of pool.
Now 1 1/2 hours = 60+30=90 min.
So in 1 min,Tony can fill 1/90 th part of pool.
Now,if all of them work together,then in 1 min,the part of the tak filled is
Lcm=90
So by equalizing the deniminators
Hence,If they all work together ,The tank will be filled in 15 minutes.
For more math help,You can reply me .
Time and work problems are very important for test preparation when you are out of school for long period .
The time will be given and the amount of work done in that time period needs to be calculated and vice versa .
Here is a simple Time word problem Given ,Which will give an idea of solving workwordproblems
as well.
Question :-
Jim can fill a pool carrying buckets of water in 30 minutes. Sue can do the same job in 45 minutes. Tony can do the same job in 1 ½ hours. How quickly can all three fill the pool together?
Answer:-
Jim can fill the pool in 30 min.
So in 1 min,jim can fill 1/30 th part of pool.
Similarly in 1 min,Sue can fill 1/45th part of pool.
Now 1 1/2 hours = 60+30=90 min.
So in 1 min,Tony can fill 1/90 th part of pool.
Now,if all of them work together,then in 1 min,the part of the tak filled is
1 1 1
= --- + ---- + ----
30 45 90
Lcm=90
So by equalizing the deniminators
1*3 1*2 1*1
------ + ----- + -------
30*3 45*2 90*1
3 2 1
= ------ + ------ + ------
90 90 90
3+2+1
= ----------
90
6
= ------
90
1
= ----
15
Hence,If they all work together ,The tank will be filled in 15 minutes.
For more math help,You can reply me .
Tuesday, May 26
Problem on parallelogram, Finding Area of parallelogram
Geometry construction section in math consists of geometrical figures like parallelogram rectangle, trapezium where we find few terms like linear pair, supplementry angles.
If a pair of angles are adjacent as well as supplementary then they are said to form a linear pair
Topic : Area of parallelogram
Below example also prove how the necessary statements are considered.
Question : In the following figure, NDBA is a rectangle, AN = NG, BF = DB, GD = 11, and DF = 8√2. What is the area of parallelogram GDFA?
If a pair of angles are adjacent as well as supplementary then they are said to form a linear pair
Topic : Area of parallelogram
Below example also prove how the necessary statements are considered.
Question : In the following figure, NDBA is a rectangle, AN = NG, BF = DB, GD = 11, and DF = 8√2. What is the area of parallelogram GDFA?
State all the statements that are necessary in your proof along with their reasons in a two-column table.
Solution :
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