A problem on simple interest

Interest is a fee paid on borrowed assets. It is the price paid for the use of borrowed money, or, money earned by deposited funds.Assets that are sometimes lent with interest include money, shares, consumer goods through hire purchase, major assets such as aircraft, and even entire factories in finance lease arrangements. The interest is calculated upon the value of the assets in the same manner as upon money. Interest can be thought of as "rent of money". For example, if you want to borrow money from the bank, there is a certain rate you have to pay according to how much you want loaned to you.

Simple interest is calculated only on the principal amount, or on that portion of the principal amount which remains unpaid.

The amount of simple interest is calculated according to the following simple interest formula:

Let's see a problem on this from 8th grade math worksheets

Question:-

What is the interest earned on # 97500 when rate of interest is 8% and for 5 months?

Answer:-

Here is the solution from answers to math problems



This problem based on simple interest.

The formula for simple interest is

    p x T x R
I= ------------
       100

p= principle=$97500

R=rate of interest =8%

T=Time of year=5 months
=5/12 in years

I=interest amount

We have to put these values in formula

  97500 x 8 x 5
I= --------------
     100 x 12

     3900000
I = ----------
      1200

 I=3250

So the total interest earned on $97500 is $3250.

This is a part of elementary algebra practice .

Problem on mean median mode range

This math help is for mean median mode range worksheets

Mean, median, and mode are three kinds of "averages".

The "mean" is the "average" you're used to, where you add up all the numbers and then divide by the number of numbers.

The "median" is the "middle" value in the list of numbers. To find the median, your numbers have to be listed in numerical order, so you may have to rewrite your list first.


The "mode" is the value that occurs most often. If no number is repeated, then there is no mode for the list.

The "range" is just the difference between the largest and smallest values.

EXAMPLE:-

Find the mean, median, mode, and range for the following list of values:
8, 9, 10, 10, 10, 11, 11, 11, 12, 13

The mean is the usual average:
(8 + 9 + 10 + 10 + 10 + 11 + 11 + 11 + 12 + 13) ÷ 10 = 105 ÷ 10 = 10.5

The median is the middle value. In a list of ten values, that will be the (10 + 1) ÷ 2 = 5.5th value; that is, average of the fifth and sixth numbers to find the median:
(10 + 11) ÷ 2 = 21 ÷ 2 = 10.5

The mode is the number repeated most often. This list has two values that are repeated three times.10 and 11.

The largest value is 13 and the smallest is 8,
so the range is 13 – 8 = 5.

So
mean: 10.5
median: 10.5
modes: 10 and 11
range: 5


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A word problem on percentages

Percentages are used to express how large one quantity is, relative to another quantity. The first quantity usually represents a part of, or a change in, the second quantity, which should be greater than zero. For example, an increase of $ 0.15 on a price of $ 2.50 is an increase by a fraction of 0.15 / 2.50 = 0.06. Expressed as a percentage, this is therefore a 6% increase.

Let's see a word problem on it.

Question:-

A waitress earn an average tip of 12% of the cost of the food she serves.If she serves $ 375 worth of food in one evening ,how much money in tips will she earn on average.

Answer:-

Waitress serves food worth=$375

She earns a tip=12%

     So.
           12% of $375


       12
      ----- * 375
       100

      12*375
     ---------
       375

       4500
   =  -------
        100

   =$45

 So the waitress earn a tip of $45.

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problem on solving linear equations

Topic:-linear equation

A linear equation is an algebraic equation in which each term is either a constant or the product of a constant and (the first power of) a single variable.

Linear equations can have one or more variables. Linear equations occur with great regularity in applied mathematics. While they arise quite naturally when modeling many phenomena, they are particularly useful since many non-linear equations may be reduced to linear equations by assuming that quantities of interest vary to only a small extent from some "background" state.

Question:-

solve |5b-3| = |3b+7|

Answer:-
This math help is from linear equations.

This is of the form |a|=|b|

which implies a = +b
        or a = -b

Using this we get

    5b-3=+(3b+7)

    5b-3=-(3b+7)

5b-3 =+(3b+7)|  5b-3 =-(3b+7)
            |
5b-3 = 3b+7 | 5b-3 = -3b-7
            |
bring 3b    |
left        | bring 3b left
hand side   | hand side
            |
5b-3b=7+3   | 5b+3b= -7+3
            |
2b = 10     | 8b= -4
            |
b = 5       | b = -4/8
            |
            | b = -1/2

So b= 5 or -1/2 is the answer

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How to solve time and work problems

Topic :- Time and Work

Time and work problems are very important for test preparation when you are out of school for long period .
The time will be given and the amount of work done in that time period needs to be calculated and vice versa .

Here is a simple Time word problem Given ,Which will give an idea of solving workwordproblems
as well.
Question :-

Jim can fill a pool carrying buckets of water in 30 minutes. Sue can do the same job in 45 minutes. Tony can do the same job in 1 ½ hours. How quickly can all three fill the pool together?

Answer:-

Jim can fill the pool in 30 min.
So in 1 min,jim can fill 1/30 th part of pool.

Similarly in 1 min,Sue can fill 1/45th part of pool.

Now 1 1/2 hours = 60+30=90 min.

So in 1 min,Tony can fill 1/90 th part of pool.

Now,if all of them work together,then in 1 min,the part of the tak filled is

   1     1      1
= --- + ---- + ----
  30     45     90

Lcm=90

So by equalizing the deniminators

 1*3      1*2     1*1
------ + ----- + -------
 30*3     45*2    90*1

    3        2        1
= ------ + ------ + ------
    90       90      90

      3+2+1
=    ----------
      90

   6
= ------
   90
   1
= ----
   15

Hence,If they all work together ,The tank will be filled in 15 minutes.


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Problem on parallelogram, Finding Area of parallelogram

Geometry construction section in math consists of geometrical figures like parallelogram rectangle, trapezium where we find few terms like linear pair, supplementry angles.
If a pair of angles are adjacent as well as supplementary then they are said to form a linear pair

Topic : Area of parallelogram

Below example also prove how the necessary statements are considered.

Question : In the following figure, NDBA is a rectangle, AN = NG, BF = DB, GD = 11, and DF = 8√2. What is the area of parallelogram GDFA?

State all the statements that are necessary in your proof along with their reasons in a two-column table.

Solution :

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Question on Integrating a Given Function

Here is a Multi choice question to Evaluate function by Integration.
You can find similar set of questions at TutorVista Blogs.

Topic : Integrating a Function.

Below example will help you to identify correct choice and get reasons for, why remaining choices are incorrect.

Question : At what point in the interval [0, √3] does the function y=x² - 1 assumes its average value.
a. -1
b. 1
c. 1.5
d. 1.7

Solution :
Choice b is correct.
Average value = 1/(√3 - 0)₀∫^√3 (x² - 1)dx = 0
And x² – 1 = 0
Therefore, y= x² -1 assumes its average at x = 1

Choice a is incorrect as -1 is not in the interval [0, √3]

Choice c is incorrect as 1.5 does not satisfy the equation x² -1=0

Choice d is incorrect as 1.7 does not satisfy the equation x² -1=0


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